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A football is punted from a height of 3. 5 feet about the ground with an initial velocity of 45 feet per second. This situation can be represented by the function −16t2 + 45t + 3. 5 , where t is the number of seconds elapsed since the football was kicked. If the football is caught at a height of 5. 5ft on the ball’s descent, when was the football in the air at that height?

Answer :

ngricky138

Answer:

h= -5.6444444444 ft

Step-by-step explanation:

h= 5.5

5.5= -16^2 + 45 t +3.5

5.5 = 256 +45t +3.5

2= 256+45t

-254= 45t

t=- 5.6444444444

I hope that's right formula for you. Thanks.

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