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2. Joshua graphs the polynomial function f(x) = x2 - 6x + z, which has a zero at (1,0) and a vertex at (3,-4). Use the given information to determine the value of z in Joshua's polynomial function. Enter the value of z below.​

Answer :

By using one of the given points and solving an equation, we will see that the constant is z = 5.

How to find the value of Z?

We know that the quadratic function is:

f(x) = x^2 - 6x + z

And we know that the vertex is (3, -4), this means that:

f(3) = -4

Replacing that in the function, we get:

-4 = 3^2 - 6*3 + z

Now we solve that for z:

-4 = 9 - 18 + z

-4 = -9 + z

-4 + 9 = z = 5

So we conclude that z = 5

If you want to learn more about quadratic functions, you can read:

https://brainly.com/question/1214333

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