Answered

Line segment AB has endpoints A(-2, 0) and B(4, 8).

Point C is on the line segment AB and is located at (2.5, 6).

What is the ratio of CB/AC

? DO NOT use the Section Formula to solve this problem.

Answer :

xero099

The ratio of [tex]\frac{CB}{AC}[/tex] is 3.

How to calculate a distance ratio in a line segment

The ratio of [tex]\frac{CB}{AC}[/tex] is the length of line segment CB divided by line segment AC. Each length is found by Pythagorean theorem:

Line segment AC

[tex]AC = \sqrt{[2.5-(-2)]^{2}+(6-0)^{2}}[/tex]

[tex]AC = 7.5[/tex]

Line segment CB

[tex]CB = \sqrt{(4-2.5)^{2}+(8-6)^{2}}[/tex]

[tex]CB = 2.5[/tex]

Finally, the ratio of [tex]\frac{CB}{AC}[/tex] is:

[tex]\frac{CB}{AC} = \frac{2.5}{7.5}[/tex]

[tex]\frac{CB}{AC} = 3[/tex]

The ratio of [tex]\frac{CB}{AC}[/tex] is 3.

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