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A jogger ran 6 miles due east of his house. Then he ran 4 miles at a heading of 30o east of north (or 30o ne). How far is he from his house after running 10 miles? group of answer choices.

Answer :

okpalawalter8

The distance he is from his house is mathematically given as

OB=8.718

The jogger's distance from his house

Question Parameters:

A jogger ran 6 miles due east of his house. Then he ran 4 miles at a heading of 30 east of north

The from his house after running 10 miles

AC/AB=cos60

Generally

[tex]OB=\sqrt{OC^2+BC^2}\\\\OB=\sqrt{6+2}^2+(2\sqrt{3})^2[/tex]

OB=8.718

Therefore,he is 8.718 miles distance from his house

For more information on distance

https://brainly.com/question/989117

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