Answer :

Oseni

0.36 g of H2 would be produced.

Stoichiometric reactions

According to the equation of the reaction: 2Al + 6HBr → 2AlBr3 + 3H2

The mole ratio of Al to HBr is 1:3.

Mole of 15.8 g Al = 15.8/26.98

                              = 0.59 mole

Mole of 29.2 g HBr = 29.2/80.91

                                 = 0.36 mole

Thus, HBr is the limiting reagent.

Mole ratio of HBr and H2 = 2:1

Equivalent mole of H2 = 0.36/2

                                      = 0.18 mole

Mass of 0.18 mole H2 = 0.18 x 2

                                     = 0.36 g

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