Answer :
The balloon’s vertical distance above the ground is 556 feet
The set up will form a right triangle.
Given the following parameters
- Angle of depression = 29 degrees
- Horizontal distance = 1004 feet
To get the height above the ground, we will use the SOH CAH TOA identity as shown;
Opposite = h
Adjacent = 1004 feet
Tan theta = h/1004
Tan 29 = h/1004
h = 1004 tan 29
h = 1004(0.5543)
h = 556.52 feet
Hence the balloon’s vertical distance above the ground is 556 feet
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