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A student uses a spring (with a spring constant of 180 N/m) to launch a marble vertically into the air. The mass of the marble is 0.004 kg and the spring is compressed 0.03 m. How high will the marble go? Answer:

Answer :

Answer:

Explanation:

Ignoring air resistance the spring compression energy will equal the increase in potential energy from the maximum spring compression point to the top of the flight arc.

mgh = ½kx²

    h = kx²/2mg

    h = 180(0.03²) / (2(0.004)(9.8))

    h = 2.06632...

    h = 2.1 m

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