Solve for R1. Thank you! :)

Answer:
[tex]\displaystyle R_1 = \frac{R_T\cdot R_2}{R_2 - R_T}[/tex]
Step-by-step explanation:
We are given the equation:
[tex]\displaystyle \frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}[/tex]
And we want to solve for R₁.
We can multiply everything by the three denominators to remove all fractions:
[tex]\displaystyle R_TR_1R_2\left(\displaystyle \frac{1}{R_T}\right) = R_TR_1R_2\left(\frac{1}{R_1} + \frac{1}{R_2}\right)[/tex]
Multiply:
[tex]\displaystyle R_1R_2 = R_TR_2 + R_TR_1[/tex]
Isolate R₁:
[tex]\displaystyle R_1R_2 - R_1R_T = R_TR_2[/tex]
We can factor:
[tex]\displaystyle R_1(R_2 - R_T) = R_TR_2[/tex]
And divide. Therefore, in conclusion:
[tex]\displaystyle R_1 = \frac{R_T\cdot R_2}{R_2 - R_T}[/tex]
Answer:
[tex]\displaystyle \rm R _{1} = \frac{ R _{T}R _{2} }{R _{2} - R _{T}}[/tex]
Step-by-step explanation:
Just an alternative.
we would like to solve the following equation for [tex]{R_1}[/tex].
[tex] \displaystyle \rm \frac{1}{R _{T} } = \frac{1}{R _{1} } + \frac{1}{R _{2} } [/tex]
in order to do so,we can simplify the right hand side which yields:
[tex] \displaystyle \rm \frac{1}{R _{T} } = \frac{R _{2} + R _{1} }{R _{1} R _{2} } [/tex]
Steps, used to simplify the right hand side:
Cross multiplication:
[tex]\displaystyle \rm R _{1} R _{2}= R _{T}(R _{2} + R _{1} )[/tex]
distribute:
[tex]\displaystyle \rm R _{1} R _{2}= R _{T}R _{2} + R _{T} R _{1} [/tex]
isolate [tex]R_1[/tex] to the left hand side and change its sign:
[tex]\displaystyle \rm R _{1} R _{2} - R _{T}R _{1}= R _{T}R _{2} [/tex]
factor out [tex]R_1[/tex] from the left hand side expression:
[tex]\displaystyle \rm R _{1} (R _{2} - R _{T})= R _{T}R _{2} [/tex]
divide both sides by [tex]R_2-R_T[/tex]:
[tex]\displaystyle \rm \frac{R _{1} (R _{2} - R _{T})}{(R _{2} - R _{T})}= \frac{ R _{T}R _{2} }{(R _{2} - R _{T})}[/tex]
reduce fraction:
[tex]\displaystyle \rm \boxed{ R _{1} = \frac{ R _{T}R _{2} }{R _{2} - R _{T}}}[/tex]
and we're done!