Answer :
Answer:
[tex]base = 14cm \\ height = 17cm[/tex]
Step-by-step explanation:
Let the length of the base be x
So length of the base = x
height = x +3
[tex]area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times b\times h \\ 119 = \frac{1}{2} \times x \times (x + 3) \\119 = \frac{ {x}^{2} + 3x }{2} \\ 119 \times 2 = {x}^{2} + 3x \\ 238 = {x}^{2} + 3x \\ 0 = {x}^{2} + 3x - 238 \\ {x}^{2} + 3x - 238 = 0 \\ {x}^{2} + 17x - 14x - 238 = 0 \\ x(x + 17) - 14(x + 17) = 0 \\ (x - 14)(x + 17) = 0 \\ \\ x - 14 = 0 \\ x = 14 \\ \\ or \\ x + 17 = 0 \\ x = - 17 \\ \\ length \: \: cannot \: \: be \: \: given \: \: as \: \: a \: \: negative \: \: number \: \: \\ \\ so \\ \: \: base \: = 14cm \\ height = x + 3 \\ = 14 + 3 \\ = 17cm[/tex]