Answer :
So we are given an equation that represents the population of fish left after so many years, so lets plug in t = 13 and see what happens:
N(13)=N0e^−.2(13)≈(.074)N0
The percentage of the fish still alive is then:
(.074)N0/ N0(100)=7.43%
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N(13)=N0e^−.2(13)≈(.074)N0
The percentage of the fish still alive is then:
(.074)N0/ N0(100)=7.43%
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.