3mstacy
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Look at the rectangle and the square:


A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 12 inches, and the width QR is labeled as 6 inches. The side LM of the square is labeled as 6 inches

Sam says that the length of diagonal SQ is two times the length of diagonal OM.


Is Sam correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.


(Sorry for the low quality image)

Look at the rectangle and the square: A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 12 inches, and the w class=

Answer :

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = [tex]\sqrt{180}[/tex] ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = [tex]\sqrt{72}[/tex] ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

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