Answer:
[tex]Area = 52\sqrt3 \ ft^2[/tex]
Step-by-step explanation:
Area of trapezoid
[tex](\frac{a+ b}{2}) \times h[/tex] -----------( 1 )
We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.
[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex] [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]
[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]
Therefore, h = 4√3 ft
[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex] [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]
[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]
Therefore, a = 11 feet, b = 11 + 4 = 15 feet
Substitute the values in the Area equation :
[tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]
