Answer :
Answer:
3.22
Explanation:
The pOH is defined as:
pOH = - log [OH⁻]
From the problem, we have [OH⁻] = 6.0 x 10⁻⁴.
Thus, we introduce the concentration in the equation to calculate the pOH:
pOH = - log [OH⁻] = -log (6.0 x 10⁻⁴) = 3.22
Answer:
3.22
Explanation:
The pOH is defined as:
pOH = - log [OH⁻]
From the problem, we have [OH⁻] = 6.0 x 10⁻⁴.
Thus, we introduce the concentration in the equation to calculate the pOH:
pOH = - log [OH⁻] = -log (6.0 x 10⁻⁴) = 3.22