What is the area of the region in the first quadrant bounded on the left by the graph of x=y4+y2 and on the right by the graph of x=5y ?
a)2.983
b)8.508
c)5005.880
d)5293.155

Answer :

Answer:

2.983

I hope it is helpful to you

The area of the region in the first quadrant bounded on the left and right by the two given graphs is; A: 2.983

What is the area bounded by the graph?

We are given the equations;

x = y⁴ + y²  ----(eq 1)

x = 5y   ----(eq 2)

Now, let us put eq 1 into eq 2 to get;

y⁴ + y² = 5y

y⁴ + y² - 5y = 0

Using online roots of polynomial calculator, we have;

y = 0 and 1.516

Thus, the area of the region will be gotten by finding the integral between those two points;

[tex]\int\limits^0_\frac{1.516}{} {y^{4} + y^{2} - 5y} \, dy[/tex]

Integrating this, we have;

[tex]\left[\begin{array}{ccc}y^{4} +y^{2} - 5y\\\\\end{array}\right]^{0}_{1.516}[/tex]

Plugging in the relevant values and subtracting gives;

Area = 2.98276 ≈ 2.983

Read more about integration at; https://brainly.com/question/19053586

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