Answer :

maacastrobr

Answer:

7.94x10⁻⁸ M

Explanation:

Using the pH given by the problem, we can calculate the pOH of the blood plasma:

  • pOH = 14 - pH
  • pOH = 14 - 6.90
  • pOH = 7.10

Then we can proceed to calculate the [OH⁻] of the blood plasma, using the definition of pOH:

  • pOH = -log[OH⁻]
  • 7.10 = -log[OH⁻]
  • -7.10 = log[OH⁻]
  • [tex]10^{-7.10}[/tex] = [OH⁻]
  • [OH⁻] = 7.94x10⁻⁸ M

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