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A horizontal force of 12 Newtons is applied to a 4.0 kg box that slides on a horizontal surface. The box starts from rest moves a horizontal distance of 10 meters and obtains a velocity of 5.0 m/s. The surface has friction. The friction force is
Group of answer choices

4.9 N.

6.0 N.

7.0 N.

6.5 N.

Answer :

andrewsikaumbwe

Answer:

7.0N

Explanation:

F=ma

v2=u2+2as

25=0+20a

a=1.25m/s2

F=ma

F=0.4×1.25

Fn=5N

F=12

12-5=Ff

=7.0N

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