Given:
[tex]L=2\dfrac{1}{2}[/tex] ft and [tex]W=3\dfrac{2}{5}[/tex] ft.
[tex]P=2L+2W[/tex]
To find:
The value of P.
Solution:
We have,
[tex]P=2L+2W[/tex]
Substituting [tex]L=2\dfrac{1}{2}[/tex] and [tex]W=3\dfrac{2}{5}[/tex], we get
[tex]P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}[/tex]
[tex]P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}[/tex]
[tex]P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}[/tex]
[tex]P=5+\dfrac{34}{5}[/tex]
Taking LCM, we get
[tex]P=\dfrac{5(5)+34}{5}[/tex]
[tex]P=\dfrac{25+34}{5}[/tex]
[tex]P=\dfrac{59}{5}[/tex]
[tex]P=11\dfrac{4}{5}[/tex]
Therefore, the value of P is [tex]11\dfrac{4}{5}[/tex] ft.