9514 1404 393
Answer:
A) ∠DHG = 96°
B) arc EF = 134°
Step-by-step explanation:
Part A:
As you have shown in your work, angle DHG is supplementary to given angle FHG:
∠DHG = 180° -∠FHG
∠DHG = 180° -84°
∠DHG = 96°
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Part B:
∠DHG is half the sum of arcs EF and DG.
96° = (1/2)(arc EF + 58°) . . . . . fill in known values
192° -58° = arc EF . . . . . . . . . . multiply by 2, subtract 58°
arc EF = 134°
