Please help! Using table of average bond energies below the (trianglesymbol)H for the reaction is ___kJ

Answer:
-217 kJ
Explanation:
ΔH = reactant energy - product energy
ΔH = [(C-H) × 2 + (C≡C)] + [2 × H-I] - [(I-C) × 2 + (C-H) × 4 + (C-C)]
ΔH = [ (413 × 2 ) + 839 + 2(299)] - [(240 × 2) + (413 × 4) + 348]
ΔH = [826 +839 + 598] - [ 480 +1652 + 348]
∴ ΔH = -217