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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 5.5 m/s.
(a) In a stiff-legged landing he comes to a halt in 1.5 ms. Find the average net force that acts on him during this time.
275735 N
(b) When he bends his knees, he comes to a halt in 0.08 s. Find the average force now.
? N
(c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b).
stiff legged landing 275735 N
bent legged landing ??? N

Answer :

okpalawalter8

Answer:

a)[tex]F_{net} =275000N[/tex]

b)[tex]F_{net}'= 386718.75N[/tex]

Explanation:

From the question we are told that:  

Man's Mass [tex]M=75kg[/tex]

Speed of man [tex]V_m=5.5m/s[/tex]

a)

Landing time [tex]t_l=1.5ms[/tex]

Generally the equation for average net force F_{ net}  is mathematically given by

[tex]F_{net} = 75 *5.5 /(0.0015) N[/tex]  

[tex]F_{net} =275000N[/tex]

b)

Landing time [tex]t=0.08s[/tex]

Generally the equation for average net force[tex]F_{ net}[/tex]  is mathematically given by

[tex]F_{net}' = impulse /time \\ F_{net}'= \frac{m * u}{t}[/tex]

[tex]F_{net}'= \frac{75 * 5.5}{0.08}[/tex]

[tex]F_{net}'= 386718.75N[/tex]

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