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What is the standard form equation of the line shown below?

Graph of a line going through negative 1, 1 and 1, 4

−3x + 2y = 5

3x − 2y = −5

y − 4 = three halves(x − 1)

y = three halvesx + five halves

What is the standard form equation of the line shown below? Graph of a line going through negative 1, 1 and 1, 4 −3x + 2y = 5 3x − 2y = −5 y − 4 = three halves( class=

Answer :

We can determine first the slope of the line as follows:

slope = y2-y1 / x2-x1
slope = 4 - 1 / 1 -(-1)
slope = 3 / 2

We use the slope-point form of a line to determine the equation. We do as follows:

y - y1 = m(x - x1)
y - 4 = 3/2(x - 1)
y = 3x/2 - 3/2 + 4
y = 3x/2 + 5/2

Therefore, the last option is correct.

Answer:D

Step-by-step explanation:

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