Answer :
Answer:
The angle is approximately [tex]31^{o}[/tex].
Step-by-step explanation:
The description i the given question can be represented with the sides of a right angled triangle.
Applying the appropriate trigonometric function, we have;
Tan θ = [tex]\frac{opposite}{adjacent}[/tex]
In the question, opposite side = 60 feet, and adjacent side = 100 feet.
Tan θ = [tex]\frac{60}{100}[/tex]
= 0.6
θ = [tex]Tan^{-1}[/tex] 0.6
= [tex]30.964^{o}[/tex]
θ = [tex]31^{o}[/tex]
The angle of elevation from the end of the shadow to the top of the pole is [tex]31^{o}[/tex].