Answer:
[tex]\mathrm{A.} \: \frac{5}{14}\cdot \frac{4}{13}\\[/tex]
Step-by-step explanation:
There are 14 marbles in total, of which 5 of them are red. Therefore, the probability that the first marble she chooses is red is [tex]\frac{5}{14}[/tex].
Since she does not replace the marble, there are now 13 marbles in total, of which 4 are red (she drew one of the red marbles on her first draw). Therefore the probability of her drawing a red marble on her second draw is [tex]\frac{4}{13}[/tex], assuming she draws a red marble on the first draw.
Thus, the probability she draws a red marble on both draws is [tex]\fbox{$\mathrm{A.} \: \frac{5}{14}\cdot \frac{4}{13}$}[/tex].
