Answer:
y=-3x+2
y = [tex]\frac{1}{5}[/tex]x - 5
Step-by-step explanation:
Question 1
It is given that;
- one of the lines has an equation of; y = -3x-7
- the given line's y-int is (0, 2) ~(The y-int is when the line crosses the y axis, hence x is zero)
- these two lines are parallel
When two lines are parallel, their slope is the same, hence the equations of the given line would look like this;
y = -3x + 2
In the slope-intercept format (which is; y = mx + b, where "m" is the slope, and "b" is the y-intercept).
Questions 2
It is given that;
- one of the lines has an equation of y = -5x + 1
- the given line's y-int is (0, -5) ~(The y-int is when the line crosses the y axis, hence x is zero)
- these two lines are perpendicular
When two lines are perpendicular, their slopes are the negatives reciprocal of each other, hence the equations of the given line would look like this;
y = [tex]\frac{1}{5}[/tex]x - 5
In the slope-intercept format (which is; y = mx + b, where "m" is the slope, and "b" is the y-intercept).
