Answer:
-180 V
Explanation:
Given that,
No. of turns, N = 150
If the field increases uniformly from 0.00 T to 0.95 T and each coil of wire has an area of 1.4 m²
The coil will move perpendicular through a uniform magnetic field in 1.1 s.
We need to find the magnitude of the induced emf in the coil. The formula for the induced emf is given by :
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{-d(BA)}{dt}\\\\=-A\dfrac{dB}{dt}[/tex]
Put all the values,
[tex]\epsilon=-NA\dfrac{dB}{dt}\\\\=-150\times 1.4\times \dfrac{0.95-0}{1.1}\\\\=-181.36\ V[/tex]
Out of four options, induced emf is (-180 V)
So, induced emf in the coil is (-180 V). Hence, the correct option is (c).
