9514 1404 393
Answer:
9 square units
Step-by-step explanation:
The base JL is a horizontal line. Its length is 5-(-1) = 6.
The height is the difference between the y-coordinate of K and the y-coordinate of the horizontal line: 4 -1 = 3.
The formula for the area of a triangle is ...
A = (1/2)bh
A = (1/2)(6)(3) = 9 . . . square units
The area of ∆JKL is 9 square units.
