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A diver dives off a 32-meter high diving board into
the water below. If the diver pushes off with an initial
horizontal velocity of 1.2 m/s, how far from the base
of the board does she land?

Answer :

Answer:

3.06 m

Explanation:

Time of fall be t .

h = ut + 1/2 g t² , h is height , u is initial vertical velocity = 0

h = 1/2 g t²

32 = .5 x 9.8 x t²

t = 2.55 s

During this period , diver will move in horizontal direction also .

Horizontal displacement during fall

=  horizontal velocity x time

= 1.2 x 2.55

= 3.06 m  

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