Answer :
[tex]f(x) = {x}^{2} - 3x + 4 \\ \frac{d}{dx} ( {x}^{2} - 3x + 4) \\ g(x) = 2x - 3[/tex]
Let g(x) = f'(x)
Substitute a in x, therefore the answer is.
[tex]g(a) = 2a - 3[/tex]
— Note that it'd be better to use f'(a) or y' instead. For this one, I let g(x) equal the derivative of f(x) —