Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidic, basic, or neutral? Show all work.
If we have [tex][H+][OH-]= Kw = 1.0 x 10^-14[/tex] Then [tex][H+]= Kw/ [OH-]= 1.0x 10^-14[/tex][tex]/ 1 x 10^-11 =1 x 10^-3 mol/L[/tex] And here is the solution - as you can see it is an acidic one : [tex]pH = - log [H+]= - log 1 x 10^-3 = 3 \ \textless \ 7[/tex]
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