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A pelican flying along a horizontal path drops a fish from a height of 4 m. The fish travels 8.0 m horizontally before it hits the water below. What is the pelican’s speed

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Answer :

Lanuel

Answer:

Speed = 8.79m/s

Explanation:

Given the following data;

Height = 4m

Horizontal distance = 8m

To find the time, we would use the second equation of motion

S = ut + ½at²

We know that acceleration due to gravity is equal to 9.8m/s²

Initial velocity, u = 0

Substituting into the equation, we have;

4 = 0(t) + ½*9.8*t²

4 = 0 + 4.9*t²

4 = 4.9t²

t² = 4/4.9

t² = 0.82

Taking the square root of both sides, we have;

t = 0.91 secs

To find the speed;

Speed = horizontal distance/time

Speed = 8/0.91

Speed = 8.79m/s

Therefore, the pelican's speed is 8.79 meters per seconds.

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