Answer :
The energy of a photon : 7.645 x 10⁻³⁴ J
Further explanation
Radiation energy is absorbed by photons
The energy in one photon can be formulated as
[tex]\large{\boxed{\bold{E\:=\:h\:.\:f}}}[/tex]
Where
h = Planck's constant (6,626.10⁻³⁴ Js)
f = Frequency of electromagnetic waves
f = c / λ , Hz
c = speed of light
= 3.10⁸ m/s
λ = wavelength ,m
wavelength λ of 2.60 ✕ 10⁻⁸ m
The energy :
[tex]\tt E=h.\dfrac{c}{\lambda}\\\\E=6.626.10^{-34}\times \dfrac{3\times 10^8}{2.6\times 10^{-8}}\\\\E=7.645\times 10^{-34}~J[/tex]