Answer:
The average acceleration of the cyclist is 5 m/s²
Explanation:
Given;
initial velocity of the cyclist, u = 10 m/s
final velocity of the cyclist, v = 20 m/s
initial time of the cyclist, t₁ = 4 seconds
final time of the cyclist, t₂ = 6 seconds
The average acceleration is given by;
[tex]a = \frac{dv}{dt}\\\\a = \frac{v-u}{t_2-t_1}\\\\a = \frac{20-10}{6-4}\\\\a = 5 \ m/s^2[/tex]
Therefore, the average acceleration of the cyclist is 5 m/s²
