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A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? Model the scenario with an equation and solve. Use complete sentences to explain whether or not your solution is reasonable.

Answer :

BobTheBlob92

Answer:

10 pounds with a dollar value of $29.70, which is $0.27 per pound

Explanation:

bean A is 0.08/pound

bean B is 0.32/pound

A+B=110

.08A+0.32(B)=29.7 comes from the mixture of 110 pounds at 0.27/pound

A=110-B

0.08(110-B)+0.32B=29.7

8.8-0.08B+0.32B=29.7

0.24B=20.9

B=87.1 pounds at 0.32=27.87

A=22.9 pounds at0.08=1.83

10 pounds with a dollar value of $29.70, which is $0.27 per pound

hope this helps

Answer:

Step-by-step explanation:

10 pounds with a dollar value of $29.70, which is $0.27 per pound

Explanation:

bean A is 0.08/pound

bean B is 0.32/pound

A+B=110

.08A+0.32(B)=29.7 comes from the mixture of 110 pounds at 0.27/pound

A=110-B

0.08(110-B)+0.32B=29.7

8.8-0.08B+0.32B=29.7

0.24B=20.9

B=87.1 pounds at 0.32=27.87

A=22.9 pounds at0.08=1.83

10 pounds with a dollar value of $29.70, which is $0.27 per pound

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