Answer :
Answer:
Missing question is "a.What is the expected number of these tweets with no reaction? b.What are the variance and standard deviation for the number of these tweets with no reaction?"
a. The expected number of these tweets with no reaction is
Let x = Tweets with no reaction
E(x) = np
n= 100, p = 0.71
E(x) = (100)(0.71)
E(x) = 71
Hence, the expected number of these tweets with no reaction is 71.
b. б² = Product of n, p and (1-p)
б² = (100)(0.71)(0.29)
б² = 71*0.29
б² = 20.59
Hence, the variance for the number of these tweets with no reaction is 20.59
б = [tex]\sqrt{Product of n, p and (1-p)}[/tex]
б = [tex]\sqrt{ (100)(0.71)(0.29)}[/tex]
б = [tex]\sqrt{71*0.29)}[/tex]
б = [tex]\sqrt{20.59}[/tex]
б = 4.54
Hence, the standard deviation for the number of these tweets with no reaction is 4.54.