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Suppose that ​10% of people are left handed. If 6 people are selected at​ random, what is the probability that exactly 2 of them are left​ handed?

Answer :

fichoh

Answer:

0.0984

Step-by-step explanation:

Given that :

Percentage that are left handed = 10%

P(left handed) = probability of success = 0.1

Number of selection (n) = 6

Number of left hands in selection (x)= exactly 2

P(6, 2) = 6C2 * 0.1^2 * (1 - 0.1)^(6-2)

P(6, 2) = 15 * 0.01 * 0.6561

P(6, 2) = 0.098415

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