Answer :

TheAnimeGirl

Answer:

[tex] \huge{ \bold{ \boxed{ \tt{( \frac{1}{2} \: ,\: \: \frac{ - 3}{2} )}}}}[/tex]

Step-by-step explanation:

[tex] \text{Let \: the \: points \: be \: A \: and \: B}[/tex]

[tex] \text{A( - 3 \: 2) } \longrightarrow \text{(x1 \: , y1)}[/tex]

[tex] \text{B(4 \: - 5)} \longrightarrow \text{(x2 \:, y2)}[/tex]

[tex] \underline{ \text{Finding \: the \: midpoint}} : [/tex]

[tex] \boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \:, \frac{y1 + y2}{2} )}}[/tex]

[tex] \sf{Midpoint = ( \frac{ - 3 + 4}{2} \: , \frac{2 + ( - 5)}{2} })[/tex]

[tex] \underline{ \text{Remember}} : [/tex]

[tex] \text{( + ) * ( - ) = ( - )}[/tex]

[tex] \text{( + ) \: * \: ( + ) = ( + )}[/tex]

[tex] \text{( - ) \: * \: ( + ) = ( - )}[/tex]

[tex] \text{( - ) \: * \: ( - ) = ( + )}[/tex]

[tex] \sf{Midpoint = ( \frac{ - 3 + 4}{2} \:, \frac{2 - 5}{2}) }[/tex]

[tex] \underline{ \text{Remember}}: [/tex]

  • The positive integers are always added but posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer

[tex] \sf{Midpoint = ( \frac{1}{2} \: , \frac{ - 3}{2} )}[/tex]

[tex] \text{Hope \: I \: helped}[/tex]!

[tex] \text{Best \: regards}[/tex]!

~[tex] \text{TheAnimeGirl}[/tex]

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