Answer :
72.3+ 39.1= 111.4°F difference. 72.3= 723/10 and -39.1= -391/10. i can’t do the rest i have to go but hope this helped
Part A
The temperature of the water (in degrees Fahrenheit) after Raul added the ice cubes is 72.3 + (-39.1).
Part B
Rewrite the expression in part A by breaking up each of the place values. In this case, the place values are tens, ones, and tenths.
72.3 + (-39.1) = 70 + 2 + 0.3 + (-30) + (-9) + (-0.1)
Part C
Next, rearrange the expression in part B using the Commutative Property so the terms with the same place value are next to each other.
70 + 2 + 0.3 + (-30) + (-9) + (-0.1) = 70 + (-30) + 2 + (-9) + 0.3 + (-0.1)
Part D
Now group the terms in the expression in part C using the Associative Property.
70 + (-30) + 2 + (-9) + 0.3 + (-0.1) = [70 + (-30)] + [2 + (-9)] + [0.3 + (-0.1)]
Part E
Simplify the expression in part D to find the temperature of the water after Raul added the ice cubes. Show your work.
Part F
Several minutes later, Raul decides to measure the water temperature again. He finds that the temperature changed by -0.6°F. What is the temperature of the water now?
The initial temperature of the water was 33.2°F. After several minutes, the temperature of the water changed by -0.6°F. So, the new temperature of the water is 33.2 + (-0.6) =
(30 + 3) + [0.2 + (-0.6)] = 33 + (-0.4) = 33 – 0.4 = 32.6°F.