Answer :
Answer:
The height of the building is 156.42 m
Step-by-step explanation:
Given;
mass of the ball, m = 0.66 kg
time of fall, t = 5.65 s
initial velocity of the ball, u = 0
Apply the following kinematic equation to determine the height of the building;
h = ut + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂ x 9.8 x 5.65²
h = 156.42 m
Therefore, the height of the building is 156.42 m
The building was 156.42 metres tall
From the question we are told that
the mass of the ball, m = 0.66 kg
the time of fall, t = 5.65 s
the initial velocity of the ball, u = 0
If we use one of the equations of motions in
h = ut + ¹/₂gt², we then have
h = (0 * t) + (0.5 * 9.8 * 5.65²)
h = 4.9 * 31.923
h = 156.42 m
The height of the building is 156.42 m
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