jbnewell11
Answered

What is an equation of the line that passes through the points (0,3) and (5,-3)? Put your answer in fully reduced form.​

Answer :

0616054242

Answer:

The equation of the line is:

y

=

5

6

x

15

6

Explanation:

The equation of the line will be in the form:

y

=

m

x

+

c

where  

m

is the slope (gradient) and  

c

is the y-intercept.

To find the slope, we use:

m

=

y

2

y

1

x

2

x

1

It doesn't matter which point we decide is  

(

x

1

,

y

1

)

and which we choose as  

(

x

2

,

y

2

, since the formula will work either way.

m

=

0

(

5

)

3

(

3

)

=

5

6

Now we can use the slope and the coordinates of one point - either will do - to find the y-intercept:

y

=

m

x

+

c

0

=

5

6

(

3

)

+

c

=

15

6

+

c

Rearranging:

c

=

0

15

6

=

15

6

Over all, then, the equation of the line is:

y

=

5

6

x

15

6

The equation of the line is:

y

=

5

6

x

15

6

Explanation:

The equation of the line will be in the form:

y

=

m

x

+

c

where  

m

is the slope (gradient) and  

c

is the y-intercept.

To find the slope, we use:

m

=

y

2

y

1

x

2

x

1

It doesn't matter which point we decide is  

(

x

1

,

y

1

)

and which we choose as  

(

x

2

,

y

2

, since the formula will work either way.

m

=

0

(

5

)

3

(

3

)

=

5

6

Now we can use the slope and the coordinates of one point - either will do - to find the y-intercept:

y

=

m

x

+

c

0

=

5

6

(

3

)

+

c

=

15

6

+

c

Rearranging:

c

=

0

15

6

=

15

6

Over all, then, the equation of the line is:

y

=

5

6

x

15

6

Step-by-step explanation:

We want to find the equation of the line that passes through the points (0, 3) and (5, -3). The linear equation is y = (-6/5)*x + 3

Linear equations:

A general linear equation is written as:

y = a*x +b

Where a is the slope and b is the y-intercept.

If the line passes through two points (x₁, y₁) and (x₂, y₂) the slope can be written as:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this case, we know that the line passes through (0, 3) and (5, -3) then the slope is:

[tex]a = \frac{-3 - 3}{5 - 0} = \frac{-6}{5}[/tex]

Then the line is:

y = (-6/5)*x + b

To get the value of b, we use the fact that the line passes through (0, 3), so we have:

3 = (-6/5)*0 + b

3 = b

Then the linear equation is just:

y = (-6/5)*x + 3

If you want to learn more about linear equations, you can read:

https://brainly.com/question/4074386

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