f(n)=5⋅(−2) n−1 f, left parenthesis, n, right parenthesis, equals, 5, dot, left parenthesis, minus, 2, right parenthesis, start superscript, n, minus, 1, end superscript Complete the recursive formula of f(n)f(n)f, left parenthesis, n, right parenthesis. f(1)=f(1)=f, left parenthesis, 1, right parenthesis, equals f(n)=f(n-1)\cdotf(n)=f(n−1)⋅f, left parenthesis, n, right parenthesis, equals, f, left parenthesis, n, minus, 1, right parenthesis, dot

Answer :

sqdancefan

9514 1404 393

Answer:

  f(1) = 5

  f(n) = f(n-1)·(-2)

Step-by-step explanation:

The explicit formula ...

  [tex]f(n)=5\cdot(-2)^{n-1}[/tex]

tells you that ...

  f(1) = 5

  f(n) = f(n-1)·(-2)

_____

If you like, you can find f(n)/f(n-1) using the explicit formula.

  [tex]\dfrac{f(n)}{f(n-1)}=\dfrac{5\cdot(-2)^{n-1}}{5\cdot{(-2)^{(n-1)-1}}}=\dfrac{5(-2)^n(-2)^{-1}}{5(-2)^n(-2)^{-2}}=(-2)^{-1+2}=-2\\[/tex]

This tells you that f(n) = -2·f(n-1), as above.

Answer:

 f(1) = 5

 f(n) = f(n-1)·(-2)

Step-by-step explanation:

Other Questions