Answer :
Answer:
[tex]x = \frac{-3 \pm i\sqrt{31}}{8}[/tex]
Step-by-step explanation:
Quadratic Formula: [tex]x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]
√-1 is imaginary number i
Step 1: Define Quadratic
8a² + 6a + 5 = 0
a = 8
b = 6
c = 5
Step 2: Plug into Quadratic Formula
[tex]x = \frac{-6 \pm \sqrt{6^2-4(8)(5)} }{2(8)}[/tex]
Step 3: Solve
[tex]x = \frac{-6 \pm \sqrt{36-160} }{16}[/tex]
[tex]x = \frac{-6 \pm \sqrt{-124} }{16}[/tex]
[tex]x = \frac{-6 \pm \sqrt{124} (\sqrt{-1} )}{16}[/tex]
[tex]x = \frac{-6 \pm i\sqrt{124}}{16}[/tex]
[tex]x = \frac{-6 \pm 2i\sqrt{31}}{16}[/tex]
[tex]x = \frac{2(-3 \pm i\sqrt{31})}{16}[/tex]
[tex]x = \frac{-3 \pm i\sqrt{31}}{8}[/tex]