Answer:
The value [tex]a = 1.1842 \ m/s^2[/tex]
Explanation:
From the question we are told that
The weight of the sky diver is [tex]W = 968 \ N[/tex]
The magnitude of the drag force is [tex]D_f = 1085 \ N[/tex]
The mass of the sky diver is [tex]m = 98.8 \ kg[/tex]
Generally the net force acting on the sky diver is mathematically represented as
[tex]F = m * a = D_f - W[/tex]
Hence the acceleration of the sky diver is mathematically represented as
[tex]a = \frac{D_f - W}{ m}[/tex]
=> [tex]a = \frac{1085 - 968}{ 98.8}[/tex]
=> [tex]a = 1.1842 \ m/s^2[/tex]
