Hi there! :)
[tex]\large\boxed{x = -5, 1}[/tex]
x² + 4x + 1 = 6
Begin factoring by moving all terms to the left-hand side of the equation:
x² + 4x + 1 - 6 = 0
x² + 4x - 5 = 0
Factor by finding terms that SUM up to 4x and MULTIPLY into -5. We get:
(x + 5)(x - 1) = 0
Use the Zero-Product property to solve the quadratic equation:
x + 5 = 0
x = - 5
x - 1 = 0
x = 1
Therefore, the solutions are x = -5, 1.
Answer:
X1=1 & X2=-5
Step-by-step explanation:
x² + 4x +1=6
x² + 4x-5=0 % in standard condition
formula:
X1=(-b+sqrt(b²-4ac))/2a; X2=(-b-sqrt(b²-4ac))/2a;
so' Here
a=1 % co-efficient of x²
b=4 % co-efficient of x
c=-5 % constant
