susandrejlella
Answered

You have four fixed-volume containers at STP. Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L. Container C has 1 mol of gas in 22.4 L. Container D has 2 mol of gas in 11.2 L. Which of the four containers have equal pressures?

A and C

A and B

B and C

C and D

Answer :

taskmasters
Container A has 0.5 mol of gas in 11.2 L.
P = nRT/V = 0.5(0.08206)(273.15) / 11.2 = 1 atm

Container B has 2 mol of gas in 22.4 L.
P = nRT/V = 2(0.08206)(273.15) / 22.4 = 2 atm

Container C has 1 mol ofgas in 22.4 L. P = nRT/V = 1(0.08206)(273.15) / 22.4 =1 atm

Container D has 2 mol of gas in 11.2 L.
P = nRT/V = 2(0.08206)(273.15) / 11.2 = 4 atm

Therefore, the correct answer from the choices is the first option, container A and C has equal pressures.
Eduard22sly

The containers that have equal pressure are A and C

How to determine the pressure

1. Container A

  • Number of mole (n) = 0.5 mole
  • Volume = 11.2 L
  • Temperature (T) = STP = 273
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

P = nRT / V

P = (0.5 × 0.0821 × 273) / 11.2

P = 1 atm

2. Container B

  • Number of mole (n) = 2 moles
  • Volume = 22.4 L
  • Temperature (T) = STP = 273
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

P = nRT / V

P = (2 × 0.0821 × 273) / 22.4

P = 2 atm

3. Container C

  • Number of mole (n) = 1 mole
  • Volume = 22.4 L
  • Temperature (T) = STP = 273
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

P = nRT / V

P = (1 × 0.0821 × 273) / 22.4

P = 1 atm

4. Container D

  • Number of mole (n) = 2 moles
  • Volume = 11.2 L
  • Temperature (T) = STP = 273
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

P = nRT / V

P = (2 × 0.0821 × 273) / 11.2

P = 4 atm

SUMMARY

  • Pressure for A = 1 atm
  • Pressure for B = 2 atm
  • Pressure for C = 1 atm
  • Pressure for D = 4 atm

From the above calculations, we can conclude that container A and C have equal pressure

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