The coordinates of the point B on AC such that AB = 1/2 BC is (3, -5.3)
How to determine the coordinates of point B?
The given parameters are:
A = (6,-7)
C = (-3,-2)
The quotient AB = 1/2 BC means that:
AB : BC = 1 : 2
The coordinate of point B is then calculated using:
B = 1/(m + n) * (mx₂ +nx₁, my₂ +ny₁)
The equation becomes
B = 1/(1 + 2) * (1 * -3 + 2 * 6, 1 * -2 + 2 * -7)
Evaluate
B = 1/3 * (9, -16)
Evaluate the product
B = (3, -5.3)
Hence, the coordinates of the point B on AC is (3, -5.3)
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