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A cart starts from rest and accelerates uniformly at 4.0 m/s2 for 5.0 s. It next maintains the velocity it has reached for 10 s. Then it slows down at a steady rate of 2.0 m/s2 for 4.0 s. What is the final speed of the car?

Answer :

osikbro

Answer:

12m/s

Explanation:

[tex]v_f=v_o+at[/tex]

Let's call the velocity that the car maintains for 10 seconds [tex]v_f_1[/tex], and the final velocity [tex]v_f_2[/tex].

[tex]v_f_1=0+(4)(5)=20m/s \\\\v_f_2=20+(-2)(4)=12m/s[/tex]

Hope this helps!

ajeigbeibraheem

A cart starts from rest and accelerates uniformly at 4.0 m/s2 for 5.0 s. The final speed of the car is 12 m/s.

The velocity of an object is usually referred to as the change rate of the object in a specified direction.

Given that:

  • the initial acceleration of the car is = 4.0 m/s²
  • time = 5.0s

Using the first equation of motion;

Let v₁ be the initial speed of the car

v₁ = u₁ + a₁t₁

Since the car starts from rest, the initial speed = 0 m/s

v = 0 + (4.0 m/s²) × 5.0 s

v = 0 + 20 m/s

v = 20 m/s

  • The final acceleration = -2.0 m/s²  (since the acceleration is decelerating)
  • time = 4.0 s

Using the same first equation of motion;

Let v₂ be the final speed of the car

v₂ = u₂ + a₂t₂

v₂ = 20 m/s + (-2 m/s²) × (4.0 s)

v₂ = (20 - 8) m/s

v₂ = 12 m/s

Therefore, we can conclude that the final speed of the car is 12 m/s.

Learn more about the speed of an object here:

https://brainly.com/question/23774048?referrer=searchResults

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