Answer :
Answer:
[tex]10.07m/s^2[/tex]
Explanation:
Information we have:
velocities:
initial velocity: [tex]v_{i}=0mph[/tex] (starts from rest)
final velocity: [tex]v_{f}=50mph[/tex]
time: [tex]t=2.22s[/tex]
Since we need the answer in [tex]m/s^2[/tex], we nees to convert the speed to meters per second:
[tex]v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s[/tex]
We find the acceleration with the following formula:
[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]
substituting the known values:
[tex]a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2[/tex]
the acceleration is 10.07[tex]m/s^2[/tex]
Answer:
The acceleration of the Cheetah is found to be 10.07 m/s²
Explanation:
We have the following data in this question:
Vf = Final Velocity of the Cheetah = 50 miles/hr
Vf = (50 miles/hr)(1 hr/ 3600 s)(1609.34 m/1 mile)
Vf = 22.35 m/s
Vi = Initial Speed of Cheetah = 0 m/s (Since, Cheetah starts from rest)
t = time interval passed = 2.22 s
So, in order to find the acceleration, we simply use the formula for acceleration, that is:
Acceleration = a = (Vf - Vi)/t
a = (22.35 m/s - 0 m/s)/2.22 s
a = 10.07 m/s²
The acceleration of the Cheetah is found to be 10.07 m/s²