Answer :
Answer:
No real roots or no real zeros.
Step-by-step explanation:
The given function is
[tex]f(x)=x^2-3x+18[/tex]
We need to find the number of real zeroes.
The given function is a quadratic function.
Let a quadratic function is [tex]f(x)=ax^2+bx+c[/tex].
If [tex]b^2-4ac<0[/tex], then the function has no real root.
If [tex]b^2-4ac=0[/tex], then the function has one real root with multiplicity 2.
If [tex]b^2-4ac>0[/tex], then the function has two real roots.
In the given function,
[tex]a=1,b=-3,c=18[/tex]
So,
[tex]b^2-4ac=(-3)^2-4(1)(18)=9-72=-63<0[/tex]
The value of discriminant is -63.
Therefore, the given function has no real root or no real zeros.
Answer:
The discriminant value of F is -63
F has 0 distinct real number zeros
Step-by-step explanation: