Answer :

Answer:

[tex]p[H+] = 10.042[/tex]

Explanation:

As we know that

[tex]pKw = pH + pOH[/tex]......eq (1)

we will calculate the pH of OH- and then we will calculate the pH of H+

So p[OH-] [tex]= - log [1.10 * 10^{-4}][/tex]

Solving the right side of the equation, we get

p[OH-]

[tex]= - [-3.958]\\= 3.958[/tex]

Now we know that

[tex]pKw = 14.0[/tex]

Substituting the value of pOH in the above equation, we get -

[tex]14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042[/tex]

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