Answer :
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
To find the slope(m), use the slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] And plug in the two points on the line
(-5, 4) = (x₁, y₁)
(-4, 7) = (x₂, y₂)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{7-4}{-4-(-5)}[/tex] (two negative signs cancel each other out and become positive)
[tex]m=\frac{7-4}{-4+5}[/tex]
[tex]m=\frac{3}{1}[/tex]
m = 3 Now that you know the slope, substitute/plug it into the equation:
y = mx + b
y = 3x + b To find b, plug in either of the points into the equation, it doesn't matter which, then isolate/get the variable "b" by itself. I will use (-5, 4)
4 = 3(-5) + b
4 = -15 + b Add 15 on both sides to get "b" by itself
4 + 15 = -15 + 15 + b
19 = b
y = 3x + 19